4b^2=17b-4

Solution for 4b^2=17b-4 equation:

4b^2=17b-4

We move all terms to the left:

4b^2-(17b-4)=0

We get rid of parentheses

4b^2-17b+4=0

a = 4; b = -17; c = +4;
Δ = b2-4ac
Δ = -172-4·4·4
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-15}{2*4}=\frac{2}{8}
=1/4
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+15}{2*4}=\frac{32}{8}
=4
$